Last updated on July 16th, 2025
We use the derivative of e^7x, which is 7e^7x, as a measuring tool for how the exponential function changes in response to a slight change in x. Derivatives help us calculate profit or loss in real-life situations. We will now talk about the derivative of e^7x in detail.
We now understand the derivative of e^7x. It is commonly represented as d/dx (e^7x) or (e^7x)', and its value is 7e^7x. The function e^7x has a clearly defined derivative, indicating it is differentiable within its domain.
The key concepts are mentioned below:
Exponential Function: e^x is the base for natural logarithms.
Chain Rule: A fundamental rule for differentiating composite functions like e^7x.
Natural Exponential Function: e^x is the natural exponential function where the base is Euler's number (approximately 2.718).
The derivative of e^7x can be denoted as d/dx (e^7x) or (e^7x)'.
The formula we use to differentiate e^7x is: d/dx (e^7x) = 7e^7x (or) (e^7x)' = 7e^7x
The formula applies to all x in the real number domain.
We can derive the derivative of e^7x using proofs. To show this, we will use the rules of differentiation. There are several methods we use to prove this, such as:
Using Chain Rule We will now demonstrate that the differentiation of e^7x results in 7e^7x
using the aforementioned method: Using Chain Rule To prove the differentiation of e^7x using the chain rule, We use the formula: Let u = 7x, then f(x) = e^u
By the chain rule: d/dx [e^u] = e^u · du/dx
Since du/dx = 7, substitute back: d/dx (e^7x) = e^7x · 7 = 7e^7x
Hence, proved.
When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky.
To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes.
Higher-order derivatives make it easier to understand functions like e^7x.
For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, which is denoted using f′′(x).
Similarly, the third derivative, f′′′(x), is the result of the second derivative and this pattern continues.
For the nth Derivative of e^7x, we generally use fⁿ(x) for the nth derivative of a function f(x), which tells us the change in the rate of change.
The exponential function e^7x has no points of discontinuity, so it is differentiable everywhere. When x = 0, the derivative of e^7x is 7e^0 = 7.
Students frequently make mistakes when differentiating e^7x. These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:
Calculate the derivative of e^7x · sin(x)
Here, we have f(x) = e^7x · sin(x). Using the product rule, f'(x) = u′v + uv′ In the given equation, u = e^7x and v = sin(x).
Let’s differentiate each term, u′ = d/dx (e^7x) = 7e^7x v′ = d/dx (sin(x)) = cos(x)
Substituting into the given equation, f'(x) = (7e^7x) · sin(x) + (e^7x) · cos(x)
Let’s simplify terms to get the final answer, f'(x) = 7e^7x sin(x) + e^7x cos(x)
Thus, the derivative of the specified function is 7e^7x sin(x) + e^7x cos(x).
We find the derivative of the given function by dividing the function into two parts. The first step is finding its derivative and then combining them using the product rule to get the final result.
A company has a sales model represented by the function S(x) = e^7x, where S represents sales over time x. Measure the rate of change in sales when x = 1.
We have S(x) = e^7x (sales model)...(1)
Now, we will differentiate the equation (1) Take the derivative e^7x: dS/dx = 7e^7x
Given x = 1 (substitute this into the derivative) dS/dx = 7e^7(1) = 7e^7
Hence, at x = 1, the rate of change in sales is 7e^7.
We find the rate of change of sales at x=1, which means that at this point, sales increase at a rate of 7e^7.
Derive the second derivative of the function y = e^7x.
The first step is to find the first derivative, dy/dx = 7e^7x...(1)
Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [7e^7x] = 7 · 7e^7x = 49e^7x
Therefore, the second derivative of the function y = e^7x is 49e^7x.
We use the step-by-step process, where we start with the first derivative, then differentiate again to find the second derivative. We simplify the terms to find the final answer.
Prove: d/dx (e^(14x)) = 14e^(14x).
Let’s start using the chain rule: Consider y = e^(14x).
To differentiate, we use the chain rule: dy/dx = e^(14x) · d/dx (14x)
Since the derivative of 14x is 14, dy/dx = e^(14x) · 14 = 14e^(14x) Hence proved.
In this step-by-step process, we used the chain rule to differentiate the equation. Then, we replace 14x with its derivative. As a final step, we simplify to derive the equation.
Solve: d/dx (e^7x/x)
To differentiate the function, we use the quotient rule: d/dx (e^7x/x) = (d/dx (e^7x) · x - e^7x · d/dx(x))/x²
We will substitute d/dx (e^7x) = 7e^7x and d/dx (x) = 1 = (7e^7x · x - e^7x · 1)/x² = (7xe^7x - e^7x)/x² = e^7x (7x - 1)/x²
Therefore, d/dx (e^7x/x) = e^7x (7x - 1)/x²
In this process, we differentiate the given function using the quotient rule. As a final step, we simplify the equation to obtain the final result.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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